Қалдықпен бағанға бөліңіз:
| \(\displaystyle -\) | \(\displaystyle 7\) | \(\displaystyle 3\) | \(\displaystyle 2\) | \(\displaystyle 6\) | ||
| \(\displaystyle -\) | ||||||
| \(\displaystyle -\) | ||||||
| \(\displaystyle 0\) |
1 қадам.
1. \(\displaystyle 7\)-ні \(\displaystyle 6\)-ға бөлеміз.
\(\displaystyle 7{\small }\)-ден максималды қанша \(\displaystyle \color{blue}{6}\)санын алуға болатынын табайық.
Яғни, \(\displaystyle 7\)-ні \(\displaystyle \color{blue}{6}\)-ға қалдықпен бөлу кезінде толымсыз бөліндіні табайық.
\(\displaystyle 7=\color{green}{1} \cdot \color{blue}{6}+1 {\small }\)болғандықтан
Онда \(\displaystyle \color{green}{1}\) алтылықты алуға болады.
Сондықтан \(\displaystyle \color{green}{1}\)-ді бөліндіге жазамыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small ?\) | \(\displaystyle \small \color{green}{1}\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
2. Әрі қарай, бағанда \(\displaystyle 7\)-ден көбейтінді\(\displaystyle \color{blue}{6}\cdot \color{green}{1}=\color{green}{6}{\small }\)азайтамыз:
| \(\displaystyle -\) | \(\displaystyle \small \color{orange}{ 7}\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small \color{green}{6}\) | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
3. \(\displaystyle 7{\underline3}2{\small }\)ондықтар разрядынан санды аламыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small {\bf 3}\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
\(\displaystyle 13{\small}\)санын алдық
2 қадам.
1. \(\displaystyle 13\)-ті \(\displaystyle 6{\small}\)-ға бөлеміз.
\(\displaystyle 13{\small}\)-тен максималды қанша \(\displaystyle \color{blue}{6}\) санын алуға болатынын табайық.
Яғни, \(\displaystyle 13\)-ті \(\displaystyle \color{blue}{6}{\small}\)-ға қалдықпен бөлу кезінде толымсыз бөліндіні табайық.
\(\displaystyle 13=\color{green}{2} \cdot \color{blue}{6} +1{\small}\) болғандықтан,
Онда \(\displaystyle \color{green}{2}\) алтылықты алуға болады.
Сондықтан \(\displaystyle \color{green}{2}\)-ні келесі санмен бөліндіге жазамыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small\color{green}{2}\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small 3\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
2. Әрі қарай, бағанда \(\displaystyle 13\)-тен көбейтінді \(\displaystyle \color{blue}{6}\cdot \color{green}{2}=\color{green}{12}{\small}\) азайтамыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small \color{cyan}{1}\) | \(\displaystyle \small \color{cyan}{3}\) | ||||
| \(\displaystyle \small \color{green}{1}\) | \(\displaystyle \small \color{green}{2} \) | |||||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
3. \(\displaystyle 73{\underline2}{\small }\) бірліктер разрядынан санды аламыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | \(\displaystyle \small ?\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small 3\) | ||||
| \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small {\bf 2}\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
\(\displaystyle 12{\small}\) санын алдық.
3 қадам.
1. \(\displaystyle 12\)-ні \(\displaystyle 6{\small }\)-ға бөлеміз.
\(\displaystyle 12{\small }\)-ден максималды қанша \(\displaystyle \color{blue}{6}\) санын алуға болатынын табайық.
Яғни, \(\displaystyle 12\)-ні \(\displaystyle \color{blue}{6}{\small }\)-ға бөлу кезінде бөліндіні табайық.
\(\displaystyle 12=\color{green}{2} \cdot \color{blue}{6}{\small}\) болғандықтан
онда \(\displaystyle \color{green}{2}\) алтылықты алуға болады.
Сондықтан \(\displaystyle \color{green}{2}\)-ні келесі санмен бөліндіге жазамыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | \(\displaystyle \small \color{green}{ 2}\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small 3\) | ||||
| \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | ||||
| \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | |||||
| \(\displaystyle \small 0\) |
2. Әрі қарай, бағанда \(\displaystyle 12\)-ден көбейтінді \(\displaystyle \color{blue}{6}\cdot \color{green}{2}=\color{green}{12}{\small }\) азайтамыз:
| \(\displaystyle -\) | \(\displaystyle \small 7\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | \(\displaystyle \small \color{green}{ 2}\) | |||
| \(\displaystyle -\) | \(\displaystyle \small 1\) | \(\displaystyle \small 3\) | ||||
| \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small \color{red}{ 1}\) | \(\displaystyle \small \color{red}{ 2}\) | ||||
| \(\displaystyle \small \color{green}{1}\) | \(\displaystyle \small \color{green}{2}\) | |||||
| \(\displaystyle \small 0\) |
\(\displaystyle 0{\small }\) санын алдық, бөлу процесі аяқталды.
Осылайша,
| \(\displaystyle -\) | \(\displaystyle \small \color{orange}{7}\) | \(\displaystyle \small 3\) | \(\displaystyle \small 2\) | \(\displaystyle \small 6\) | ||
| \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | \(\displaystyle \small 2\) | |||
| \(\displaystyle -\) | \(\displaystyle \small \color{cyan}{1}\) | \(\displaystyle \small \color{cyan}{3}\) | ||||
| \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | |||||
| \(\displaystyle -\) | \(\displaystyle \small \color{red}{ 1}\) | \(\displaystyle \small \color{red}{ 2}\) | ||||
| \(\displaystyle \small 1\) | \(\displaystyle \small 2\) | |||||
| \(\displaystyle \small 0\) |