Найти произведение:
\(\displaystyle \times\) | \(\displaystyle 5\) | \(\displaystyle 8\) | |
\(\displaystyle 2\) | |||
1. Умножаем единицы числа \(\displaystyle \color{blue}{5}\color{green}{8}\) (это цифра \(\displaystyle \color{green}{8}\)) на \(\displaystyle 2 \):
\(\displaystyle \color{green}{8}\cdot 2=\color{blue}{1}\color{green}{6}{\small .}\)
Пишем единицы числа \(\displaystyle \color{blue}{1}\color{green}{6} \) (это цифра \(\displaystyle \color{green}{6}\)) под единицами, а десятки числа \(\displaystyle \color{blue}{1}\color{green}{6} \) (это цифра \(\displaystyle \color{blue}{1}\)) запоминаем и будем использовать во втором действии.
1 | |||
\(\displaystyle \times\) | \(\displaystyle \color{blue}{5}\) | \(\displaystyle \color{green}{8}\) | |
\(\displaystyle 2\) | |||
\(\displaystyle ?\) | \(\displaystyle ?\) | \(\displaystyle \color{green}{6}\) |
2. Умножаем десятки числа \(\displaystyle \color{blue}{5}\color{green}{8}\) (это цифра \(\displaystyle \color{blue}{5}\)) на \(\displaystyle 2 \):
\(\displaystyle \color{blue}{5}\cdot 2=\color{blue}{10}{\small .}\)
Используем \(\displaystyle \color{blue}{1}\) с предыдущего действия, складывая с произведением десятков:
\(\displaystyle \color{blue}{10}+\color{blue}{1}=\color{blue}{11}{\small .}\)
1 | |||
\(\displaystyle \times\) | \(\displaystyle \color{blue}{5}\) | \(\displaystyle \color{green}{8}\) | |
\(\displaystyle 2\) | |||
\(\displaystyle \color{blue}{1}\) | \(\displaystyle \color{blue}{1}\) | \(\displaystyle \color{green}{6}\) |
Ответ: \(\displaystyle 116 {\small .}\)