Бізге берілген көпмүшелерді стандарт түрге келтірейік:

\(\displaystyle \quad \begin{array}{l}{\small 1)\,}2xyz^{\, 2}\cdot 3xz\cdot y-4xy^{\,2}z^{\,3}=(2\cdot 3)\cdot (x\cdot x\,)\cdot (\,y\cdot y\,)\cdot (z^{\, 2}\cdot z\,)-4xy^{\,2}z^{\,3}=\\[10pt]\kern{10em} =6\cdot x^{\,1+1}\cdot y^{\,1+1}\cdot z^{\,2+1}-4xy^{\,2}z^{\,3}=6x^{\,2}y^{\,2}z^{\,3}-4xy^{\,2}z^{\,3}\,{\small ;}\end{array}\)

\(\displaystyle \quad \begin{array}{l}{\small 2)\,}-xz\cdot 5yz\cdot yz-6zy\cdot x^{\,2}y\cdot z^{\,2}=\\[10pt]\kern{5em} =-5\cdot x\cdot (\,y\cdot y\,)\cdot (z\cdot z\cdot z\,)-6\cdot x^{\,2}\cdot (\,y\cdot y\,)\cdot (z\cdot z^{\,2})=\\[10pt]\kern{11em} =-5\cdot x\cdot y^{\,1+1}\cdot z^{\,1+1+1}-6\cdot x^{\,2}\cdot y^{\,1+1}\cdot z^{\,1+2}=\\[10pt]\kern{24em} =-5xy^{\,2}z^{\,3}-6x^{\,2}y^{\,2}z^{\,3}{\small .}\end{array}\)

Демек, бізге көпмүшелерді қосу керек

\(\displaystyle \color{blue}{6x^{\,2}y^{\,2}z^{\,3}-4xy^{\,2}z^{\,3}}\)

және

\(\displaystyle \color{green}{-5xy^{\,2}z^{\,3}-6x^{\,2}y^{\,2}z^{\,3}}{\small .}\)

Олардың қосындысын жазайық:

\(\displaystyle (\color{blue}{6x^{\,2}y^{\,2}z^{\,3}-4xy^{\,2}z^{\,3}}\,)+(\color{green}{-5xy^{\,2}z^{\,3}-6x^{\,2}y^{\,2}z^{\,3}}\,){\small .}\)

Жақшаларды ашайық:

\(\displaystyle \begin{array}{l}(6x^{\,2}y^{\,2}z^{\,3}-4xy^{\,2}z^{\,3}\,)+(-5xy^{\,2}z^{\,3}-6x^{\,2}y^{\,2}z^{\,3}\,)=\\[10pt]\kern{10em} =6x^{\,2}y^{\,2}z^{\,3}-4xy^{\,2}z^{\,3}-5xy^{\,2}z^{\,3}-6x^{\,2}y^{\,2}z^{\,3}{\small .}\end{array}\)

Ұқсас мүшелерді келтірейік:   

\(\displaystyle \begin{array}{l}6\color{blue}{x^{\,2}y^{\,2}z^{\,3}}-4\color{green}{xy^{\,2}z^{\,3}}-5\color{green}{xy^{\,2}z^{\,3}}-6\color{blue}{x^{\,2}y^{\,2}z^{\,3}}=\\[10pt]\kern{5em}=(6\color{blue}{x^{\,2}y^{\,2}z^{\,3}}-6\color{blue}{x^{\,2}y^{\,2}z^{\,3}})+(-4\color{green}{xy^{\,2}z^{\,3}}-5\color{green}{xy^{\,2}z^{\,3}})=\\[10pt]\kern{15em} =(6-6)\color{blue}{x^{\,2}y^{\,2}z^{\,3}}+(-4-5)\color{green}{xy^{\,2}z^{\,3}}=\\[10pt]\kern{20em} =0\cdot \color{blue}{x^{\,2}y^{\,2}z^{\,3}}-9\color{green}{xy^{\,2}z^{\,3}}=-9\color{green}{xy^{\,2}z^{\,3}}{\small .}\end{array}\)

Жауабы: \(\displaystyle -9xy^{\,2}z^{\,3}{\small .}\)