1. Делим \(\displaystyle 53\) на \(\displaystyle 53\) с остатком.
Найдем, какое максимальное количество \(\displaystyle \color{blue}{53}\) можно забрать из \(\displaystyle 53{\small .}\)
То есть найдем неполное частное при делении \(\displaystyle 53\) на \(\displaystyle \color{blue}{53}\) с остатком.
Так как
\(\displaystyle 53=\color{green}{1} \cdot \color{blue}{53}+0{\small ,}\)
то \(\displaystyle 53 \) можно забрать \(\displaystyle \color{green}{1}\) раз.
Поэтому пишем \(\displaystyle \color{green}{1}\) в частное:
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\(\displaystyle -\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
\(\displaystyle \small 1\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 9\) |
\(\displaystyle \small 53\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small \color{green}{1}\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle -\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small 0\) |
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2. Далее, вычитаем в столбик из \(\displaystyle 53\) произведение \(\displaystyle \color{blue}{53}\cdot \color{green}{1}=\color{green}{53}{\small : }\)
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\(\displaystyle -\) |
\(\displaystyle \small \color{orange}{5}\) |
\(\displaystyle \small \color{orange}{3}\) |
\(\displaystyle \small 1\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 9\) |
\(\displaystyle \small 53\) |
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\(\displaystyle \small \color{green}{ 5}\) |
\(\displaystyle \small \color{green}{ 3}\) |
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\(\displaystyle \small 1\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle -\) |
\(\displaystyle \small 0\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small 0\) |
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3. Сносим цифру из разряда сотен \(\displaystyle 53{\underline 1}59{\small : }\)
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\(\displaystyle -\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
\(\displaystyle \small 1\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 9\) |
\(\displaystyle \small 53\) |
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\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
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\(\displaystyle \small \color{green}{1}\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle -\) |
\(\displaystyle \small 0\) |
\(\displaystyle \small \color{red}{ 1}\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small 0\) |
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4. Так как \(\displaystyle \color{red}{ 1}\) меньше, чем \(\displaystyle 53{\small ,}\) то сносим следующую цифру (десятки числа \(\displaystyle 531{\underline 5}9{\small ,}\) то есть цифру \(\displaystyle 5\)), а в частном записываем нуль:
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\(\displaystyle -\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
\(\displaystyle \small 1\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 9\) |
\(\displaystyle \small 53\) |
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\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
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\(\displaystyle \small 1\) |
\(\displaystyle \small \color{green}{ 0}\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle -\) |
\(\displaystyle \small 0\) |
\(\displaystyle \small \color{red}{ 1}\) |
\(\displaystyle \small \color{red}{ 5}\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small 0\) |
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5. Так как \(\displaystyle \color{red}{ 15}\) меньше, чем \(\displaystyle 53{\small ,}\) то сносим следующую цифру (единицы числа \(\displaystyle 5315{\underline 9}{\small ,}\) то есть цифру \(\displaystyle 9\)), а в частном записываем нуль:
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\(\displaystyle -\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
\(\displaystyle \small 1\) |
\(\displaystyle \small 5\) |
\(\displaystyle \small 9\) |
\(\displaystyle \small 53\) |
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\(\displaystyle \small 5\) |
\(\displaystyle \small 3\) |
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\(\displaystyle \small 1\) |
\(\displaystyle \small 0\) |
\(\displaystyle \small \color{green}{ 0}\) |
\(\displaystyle \small ?\) |
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\(\displaystyle -\) |
\(\displaystyle \small 0\) |
\(\displaystyle \small \color{red}{ 1}\) |
\(\displaystyle \small \color{red}{ 5}\) |
\(\displaystyle \small \color{red}{ 9}\) |
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\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
\(\displaystyle \small ?\) |
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\(\displaystyle \small 0\) |
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Получили число \(\displaystyle 159{\small .}\)
